Remove ambiguous comments.

移除有歧义的注释。

scripts/inventory/ItemSlotNode.cs

@@ -12,7 +12,6 @@ namespace ColdMint.scripts.inventory;
 /// </summary>
 public partial class ItemSlotNode : MarginContainer
 {
-    //private IItem? _item;
     private IItemStack? _itemStack;
     private TextureRect? _backgroundTextureRect;
     private TextureRect? _iconTextureRect;

scripts/item/IItem.cs

@@ -71,10 +71,6 @@ public interface IItem
     /// <para>If this item need a special stack type, return the special item stack instance that contains the item. If else, just leave this null.</para>
     /// <para>如果该项目需要特殊的物品堆类型，重写此方法来返回包含该物品的特殊物品堆实例。否则，保留原本的null返回值。</para>
     /// </summary>
-    /// <remarks>
-    /// <para>DO NOT use this method to create stack from item, use <see cref="IItemStack.FromItem"/> instead</para>
-    /// <para>不要使用此方法从一个物品创建堆，请使用 <see cref="IItemStack.FromItem"/></para>。
-    /// </remarks>
     /// <seealso cref="CanStackWith"/>
     IItemStack? SpecialStack() => null;
 }

scripts/item/itemStacks/IItemStack.cs

@@ -159,6 +159,10 @@ public interface IItemStack
     /// <para>Create a new ItemStack with the given item as the first item</para>
     /// <para>以给定的物品为第一个物品创建物品堆</para>
     /// </summary>
+    /// <remarks>
+    ///<para>Assuming the item implements the <see cref="IItem.SpecialStack"/> method, then use the return value of the SpecialStack method, otherwise extrapolate from the maximum number of stacks of items.</para>
+    ///<para>假设物品实现了<see cref="IItem.SpecialStack"/>方法，那么使用SpecialStack方法的返回值，否则根据物品的最大堆叠数量来推断。</para>
+    /// </remarks>
     public static IItemStack FromItem(IItem item) =>
         item.SpecialStack() ??
         ItemTypeManager.MaxStackQuantityOf(item.Id) switch